Since NaN != NaN you could also do (a === b) || ((a != a) && (b != b)) | Hacker News

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asynchrony on Feb 14, 2012 | parent | context | favorite | on: JavaScript: Warts and workarounds

Since NaN != NaN you could also do (a === b) || ((a != a) && (b != b))

underwater on Feb 15, 2012 [–]

I don't know why you'd use a != a instead of isNaN(a). The former hides what you're doing. Though treating two NaN values as equal doesn't even make sense in the first place.

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